On Tue, Dec 8, 2009 at 5:20 PM, Paul Mattal
Allan McRae wrote:
Paul Mattal wrote:
Regarding the below:
http://wiki.archlinux.org/index.php/DeveloperWiki:Building_in_a_Clean_Chroot
It reads:
"The -C and -M flags are optional, but it is recommended to provide these with clean pacman.conf and makepkg.conf files (directly from the pacman package) during first creation of clean chroot to ensure lack of user specific adjustments."
I think this is misleading. If you *don't* provide these arguments, what you get is the default config files directly from the pacman package, right? So the desired thing in most circumstances is, presumably, NOT to override?
I believe it copies the local ones on your file system. Perhaps that should be changed...
After building my chroot, the resulting pacman.conf inside it was different than my /etc/pacman.conf. I didn't see anything in mkarchroot to suggest it was doing anything special to those files unless the options are passed in, so it seemed to me like it must be, by default, just installing the default ones along with the pacman package.
Can anyone confirm that's the intended behavior? It seems to be how it works, unless I'm missing something.
If the -C or -M flags are specified, it will copy that file into the chroot. If not specified, it does nothing (leaving the stock files from the packages installed). Additionally, the -C config is used when running pacman to build the chroot. If you want to use a specific pacman.conf for the building but NOT copy it to the chroot, the -n flag does that. The intent here was to, do something like "mkarchroot -C /etc/pacman-i686.conf -n foo/ base base-devel" to build an i686 chroot on an x86_64 system.