On Mon, Oct 14, 2019 at 3:48 PM siefke_listen@web.de <siefke_listen@web.de> wrote:

Hello,

I have a question about grep, okay yes is not direct Arch but I not find a information and here on list sure some profis with grep.

The folder structure:

content/de/blog/*.md content/fr/blog/*.md content/en/blog/*.md content/ru/blog/*.md

To know which articles I have translate I grep through dates:

grep -e "2019-10-1" content/blog/de (for the dates between 10 and 19)

I become:

grep -e "2019-10-1" content/de/blog/* content/de/blog/file1.md:date: 2019-10-10 content/de/blog/file2.md:date: 2019-10-12 content/de/blog/file3.md:date: 2019-10-14 content/de/blog/file4.md:date: 2019-10-16

Now is my question,

How can I do the same in the other folders and all those that exist with the same date are hidden and when no file is present give out the file which is missing in other folders sort by date. The name of file is sure other, but the date is ever the same.

grep -e "2019-10-1" content/en/blog/* No output > all files translated

grep -e "2019-10-1" content/fr/blog/* content/de/blog/file4.md:date: 2019-10-16 > file is missed

grep -e "2019-10-1" content/ru/blog/* content/de/blog/file3.md:date: 2019-10-14 > file is missed content/de/blog/file4.md:date: 2019-10-16 > file is missed

Grep to the first folder (de) as a comparison to the others (en,fr,ru).

I had try it with diff but it want not work.

Would be great there is a idea.

Thank you for help.

Silvio

I'm having a very difficult time deciding what you are asking, but perhaps this is helpful. It sounds like you want to make sure each language has the same files in it? For instance, given the existence of the files: content/en/blog/file1.md content/en/blog/file2.md content/en/blog/file3.md You want some sort of warning to be issued if only the following files exist in another directory: content/de/blog/file1.md content/de/blog/file3.md Is that correct? If so, you'll do something like for file in content/en/blog/*.md; do basefile=$(basename "$file" .md) if [[ ! -e content/de/blog/"$basefile" ]]; then echo "German is missing $basefile"; fi; done; Perhaps? Maybe instead you're saying that the dates present in one language should also be present in another language? That would be a pretty different solution with which I'm happy to help if you indicate such a desire.

Hey hey Silvio, hm this looks more like a challenge for a whole script. I can script, but I'm not always the most efficient. If your .md files always look the same, i.e. there is always the exact line "date: yyyy-mm-dd" and you can be sure that one script folder will have all articles, because they are originally written in that language, I'd have an idea. Say your articles are all created in German: grep -e "date: 2019-10-1" content/de/blog/*.md >orig.list LINES=`wc -l orig.list | awk '{ print $2 }'` # get number of entries # do the same for the ohter folders: grep -e "date: 2019-10-1" content/en/blog/*.md >en.list grep -e "date: 2019-10-1" content/fr/blog/*.md >fr.list # complete for other folders # now check CURLINE=1 while [[ $CURLINE -le $LINES ]]; do CURDATE=`sed -n ${CURLINE}p orig.list # get an article date for FILE in en.list fr.list ru.list and_so_on; do COUNT=`grep -c -e "${CURDATE}" ${FILE} if [[ $COUNT -eq 0 ]]; then # not found in translation echo ${CURDATE} missing in ${FILE}" >missing.files; fi; done let CURLINE=CURLINE+1; # go to next original date done rm *.list # remove your temporary files You can beautify the echo line, at the moment this would write something like: date: 2019-10-12 ru.list But it should do. I'm sure a more elegant script can be written. Best wishes, Jeanette -- * Website: http://juliencoder.de - for summer is a state of sound * Youtube: https://www.youtube.com/channel/UCMS4rfGrTwz8W7jhC1Jnv7g * SoundCloud: https://soundcloud.com/jeanette_c * Twitter: https://twitter.com/jeanette_c_s * Audiobombs: https://www.audiobombs.com/users/jeanette_c * GitHub: https://github.com/jeanette-c I thought love was just a tingling of the skin <3 (Britney Spears)

Hi Silvio,

How can I do the same in the other folders and all those that exist with the same date are hidden and when no file is present give out the file which is missing in other folders sort by date. The name of file is sure other, but the date is ever the same.

The requirement is unclear. Given this input, $ grep ^ */* de/1.md:date: 2019-10-10 de/2.md:date: 2019-10-12 de/3.md:date: 2019-10-14 de/4.md:date: 2019-10-16 en/1.md:date: 2019-10-10 en/2.md:date: 2019-10-12 en/3.md:date: 2019-10-14 en/4.md:date: 2019-10-16 fr/4.md:date: 2019-10-16 ru/3.md:date: 2019-10-14 ru/4.md:date: 2019-10-16 $ what output do you require? -- Cheers, Ralph.