15 Jan
2014
15 Jan
'14
4:03 p.m.
On Wed, Jan 15, 2014 at 9:50 AM, Allan McRae <allan@archlinux.org> wrote: [...]
+ # hash function (x*2+1) is completely arbitrary. + my $repohash = $v[0]; + $repohash =~ s/(.)/ord($1)*2+1/ge;
I have very little perl knowledge, so I have no idea what that hash is doing. Can someone explain to me so I can see if that "hash" is reasonable.
Replace each character with its [0] ascii index times two plus one? 'g' is group regexes, 'e' is eval expressions [1], as to utilize the result of the calculation. cheers! mar77i [0] http://perldoc.perl.org/functions/ord.html [1] http://stackoverflow.com/questions/6082219/perl-regex-e-eval-modifier-with-s