[pacman-dev] bash argument passing help

[Dan McGee]

On Tue, Oct 20, 2009 at 9:45 PM, Allan McRae <allan at archlinux.org> wrote:
> Hi all,
>
> This problem has been doing my head in...    First a minimal example that
> reflects how makepkg does things:
>
> --one.sh--
> #!/bin/bash
>
> echo "pass 1:"
> for arg in "$@"; do
>  echo $arg
> done
> echo
>
> ARGLIST="$@"
>
> ./two.sh $ARGLIST
> --end one.sh--
>
> --two.sh--
> #!/bin/bash
>
> echo "pass 2:"
> for arg in "$@"; do
>  echo $arg
> done
> --end two.sh--
>
> then run:
> ./one.sh -f -h "foo bar"
> pass 1:
> -f
> -h
> foo bar
>
> pass 2:
> -f
> -h
> foo
> bar
>
>
> Note how in pass two, foo and bar are no longer in the one line.   Of
> course, passing ./two.sh "$@" works, but the argument parsing in makepkg
> clears that, hence the need to save it to ARGLIST.
>
> Any ideas?

Of course! I think I got it.

dmcgee at kilkenny /tmp
$ ./one.sh -f -h "foo bar"
pass 1:
-f
-h
foo bar

pass 2:
-f
-h
foo
bar

dmcgee at kilkenny /tmp
$ ./one-new.sh -f -h "foo bar"
pass 1:
-f
-h
foo bar

pass 2:
-f
-h
foo bar

$ cat one-new.sh
#!/bin/bash
echo "pass 1:"
for arg in "$@"; do
  echo $arg
done
echo

ARGLIST=("$@")

./two.sh "${ARGLIST[@]}"

Do I win a prize or anything? :P

-Dan